How do you solve by completing the square $2x^2+4x+12=0$ ?

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How do you solve by completing the square $2x^2+4x+12=0$ ?

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Answer 1 · 2015-04-01T23:42:46

Start by writing:
$2x^2+4x=-12$
$x^2+4/2x=-12/2$
$x^2+2x=-6$
$x^2+2x+1-1=-6$
$(x+1)^2=-6+1$
$(x+1)^2=-5$
$(x+1)=+-sqrt(-5)$
You have a negative squre root!
Did you see complex numbers yet?
If NOT stop here and say "no real solutions".
If YES:
$x=-1+-isqrt(5)$

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How do you solve by completing the square $2x^2+4x+12=0$ ?

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