How do you solve $9x^2+342x+3230=0$ by completing the square?

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Answer 1 · 2016-06-27T18:24:11

$x= - 19 pm sqrt(19)/3$

$9x^2+342x+3230=0$

$x^2+38x+3230/9=0$

$(x+19)^2 - 19^2+3230/9=0$
$= (x+19)^2 - 19/9=0$

$(x+19)^2 = 19/9$

$(x+19) = pm sqrt(19/9) = pm sqrt(19)/3$

$x= - 19 pm sqrt(19)/3$

How do you solve 9x^2+342x+3230=0 9x^2+342x+3230=0 by completing the square?