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How do you solve #9- 4( 2x + 5) = - 11#?

1 Answer

Mar 12, 2018

#x=0#

Explanation:

We can start by distributing the #-4# to the terms in the parenthesis. Here, we are just multiplying. We get:

#9-8x-20=-11#

We can combine the like terms on the left to get:

#-11-8x=-11#

The #-11#s on both sides will cancel, resulting in zero, so we're left with #-8x=0#, which will obviously evaluate to #x=0#.

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