How do you solve #8x-(x-5)>x+17#?

1 Answer
Alan P.
May 2, 2016

#x > 2#

Explanation:

Given
#color(white)("XXX")8x-(x-5) > x+17#

Remember that valid operations that maintain the validity and direction of an inequality include:
a) addition or subtraction of the same amount to both sides;
b) multiplication or division of both sides by the same amount provided that amount is greater than zero.

#rArr#
#color(white)("XXX")7x+5 > x+17#

#color(white)("XXX")6x > 12#

#color(white)("XXX")x > 2#

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