How do you solve $8x^2 - 5x - 3 = 0$ by completing the square?

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Answer 1 · 2016-08-16T12:49:35

$x=1, -3/8$

$8x^2-5x=3$

$x^2-5/8x=3/8$

$x^2-10/16x=3/8$

$x^2-10/16x+25/256=3/8+25/256$

$(x-5/16)^2=121/256$

$x-5/16=+-11/16$

$x=(+-11/16)+5/16$

$x=(5+-11)/16$

$x=1, -3/8$

How do you solve 8x^2 - 5x - 3 = 08x^2 - 5x - 3 = 0 by completing the square?