How do you solve $6x = 4x^2 -1$ by completing the square?

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Answer 1 · 2017-08-24T12:13:26

$x = 1/4(3 +-sqrt13)$

$6x = 4x^2 -1 or 4x^2 -6x =1 or 4(x^2-3/2x) =1$ or

$4(x^2-3/2x + 9/16) =1 +9/4$ [Add 9/4 on both side] or

$4(x-3/4)^2 = 13/4 or (x-3/4)^2 = 13/16$ or

$(x-3/4) = +- sqrt(13/16 ) or x = 3/4 +- sqrt13/4$

$or x = 1/4(3 +-sqrt13)$ [Ans]

How do you solve 6x = 4x^2 -16x = 4x^2 -1 by completing the square?