How do you solve #-6=2(p-3)+4(p+6)# using the distributive property?

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Answer 1 · 2018-04-08T19:06:48

#p=-4#

Distribute: #a(b+c)=a*b+a*c#

#-6=2*p-2*3+4*p+4*6#

#-6=2p-6+4p+24#

Combine like terms and evaluate:

#-6=6p+18#

#-24=6p#

#p=-4#