How do you solve $-6=2(p-3)+4(p+6)$ using the distributive property?

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Answer 1 · 2018-04-08T19:06:48

$p=-4$

Distribute: $a(b+c)=a*b+a*c$

$-6=2*p-2*3+4*p+4*6$

$-6=2p-6+4p+24$

Combine like terms and evaluate:

$-6=6p+18$

$-24=6p$

$p=-4$

How do you solve -6=2(p-3)+4(p+6)-6=2(p-3)+4(p+6) using the distributive property?