How do you solve $4 (b + 6) = 2 (b + 5) + 2$ $4(b + 6) = 2(b + 5) + 2$ ?

Question

2126 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-05-04T22:19:14

$b = - 6$ $b=-6$

You distribute the $4$ $4$ to the binomial of $(b + 6)$ $(b+6)$ and the $2$ $2$ to the binomial of $(b + 2)$ $(b+2)$

$4 (b + 6) = 2 (b + 5) + 2$ $4(b+6)=2(b+5)+2$

$4 b + 24 = 2 b + 10 + 2$ $4b+24=2b+10+2$
Combine any like terms

$4 b + 24 = 2 b + 12$ $4b+24=2b+12$
Subtract $12$ $12$ from both sides.

$4 b + 12 = 2 b$ $4b+12=2b$
Subtract $4 b$ $4b$ from both side

$12 = - 2 b$ $12=-2b$
Divide both sides by $- 2$ $-2$

$- 6 = b$ $-6=b$

Check:

$4 (- 6 + 6) = 2 (- 6 + 5) + 2$ $4(-6 + 6)=2(-6+5)+2$
$4 (0) = 2 (- 1) + 2$ $4(0) = 2(-1)+2$
$0 = - 2 + 2$ $0=-2+2$
$0 = 0$ $0=0$

This answer works.

How do you solve 4(b+6)=2(b+5)+2 4(b + 6) = 2(b + 5) + 2?