How do you solve $4(b + 6) = 2(b + 5) + 2$ ?

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Answer 1 · 2018-05-04T22:19:14

$b=-6$

You distribute the $4$ to the binomial of $(b+6)$ and the $2$ to the binomial of $(b+2)$

$4(b+6)=2(b+5)+2$

$4b+24=2b+10+2$
Combine any like terms

$4b+24=2b+12$
Subtract $12$ from both sides.

$4b+12=2b$
Subtract $4b$ from both side

$12=-2b$
Divide both sides by $-2$

$-6=b$

Check:

$4(-6 + 6)=2(-6+5)+2$
$4(0) = 2(-1)+2$
$0=-2+2$
$0=0$

This answer works.

How do you solve 4(b + 6) = 2(b + 5) + 2 4(b + 6) = 2(b + 5) + 2?