How do you solve #4 - 2(v - 6)= - 8#?

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Answer 1 · 2017-07-22T18:20:08

See a solution process below:

First, subtract #color(red)(4)# from each side of the equation to isolate the term with parenthesis while keeping the equation balanced:

#-color(red)(4) + 4 - 2(v - 6) = -color(red)(4) - 8#

#0 - 2(v - 6) = -12#

#-2(v - 6) = -12#

Next, divide each side of the equation by #color(red)(-2)# to eliminate the need for parenthesis while keeping the equation balanced:

#(-2(v - 6))/color(red)(-2) = -12/color(red)(-2)#

#(color(red)(cancel(color(black)(-2)))(v - 6))/cancel(color(red)(-2)) = 6#

#v - 6 = 6#

Then, add #color(red)(6)# to each side of the equation to solve for #v# term while keeping the equation balanced:

#v - 6 + color(red)(6) = 6 + color(red)(6)#

#v - 0 = 12#

#v = 12#