How do you solve $(3x - 5) ( x - 2 ) < 0$ ?

Question

1631 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2015-11-07T21:25:07

$x in (5/3,2)$

$(3x-5)(x-2)$ is the equation of a parabola
with x-intercepts at $5/3$ and $2$

If expanded into standard form the leading term is $3x^2$

$rArr$ the leading term coefficient is positive

$rArr$ the parabola opens upward

$rArr$ the points between the x-intercepts are below the X-axis

$rArr$ the value of the parabola is $< 0$ when $x in (5/3, 2)$

How do you solve (3x - 5) ( x - 2 ) < 0 (3x - 5) ( x - 2 ) < 0 ?