How do you solve $3 x^{2} + 18 x + 15 = 0$ $3x^2 + 18x + 15 = 0$ by completing the square?

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How do you solve $3 x^{2} + 18 x + 15 = 0$ $3x^2 + 18x + 15 = 0$ by completing the square?

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Answer 1 · 2016-01-27T16:09:30

x = -1

Explanation:

Divide both sides of the equation by 3, which yields $x^{2} + 6 x + 5 = 0$ $x^2+6x+5=0$ . Add 4 to both sides of the equation, which yields $x^{2} + 6 x + 9 = 4$ $x^2+6x+9=4$ . This is done to make the left side ${(x + 3)}^{2}$ $(x+3)^2$ . Taking the square root of both sides yields $x + 3 = 2$ $x+3=2$ . Hence, $x = - 1$ $x=-1$ .

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How do you solve $3 x^{2} + 18 x + 15 = 0$ $3x^2 + 18x + 15 = 0$ by completing the square?

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How do you solve $3 x^{2} + 18 x + 15 = 0$ $3x^2 + 18x + 15 = 0$ by completing the square?