How do you solve $3 x^{2} - 12 x + 5 = 0$ $3x^2 - 12x + 5=0$ by completing the square?

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How do you solve $3 x^{2} - 12 x + 5 = 0$ $3x^2 - 12x + 5=0$ by completing the square?

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Answer 1 · 2015-05-01T12:41:26

Write it as:
$x^{2} - \frac{12}{3} x = - \frac{5}{3}$ $x^2-12/3x=-5/3$
$x^{2} - 4 x = - \frac{5}{3}$ $x^2-4x=-5/3$ add and subtract 4
$x^{2} - 4 x + 4 - 4 = - \frac{5}{3}$ $x^2-4x+4-4=-5/3$
${(x - 2)}^{2} - 4 = - \frac{5}{3}$ $(x-2)^2-4=-5/3$
${(x - 2)}^{2} = 4 - \frac{5}{3}$ $(x-2)^2=4-5/3$
${(x - 2)}^{2} = \frac{7}{3}$ $(x-2)^2=7/3$
$x - 2 = \pm \sqrt{\frac{7}{3}}$ $x-2=+-sqrt(7/3)$
Finally:
$x_{1, 2} = 2 \pm \sqrt{\frac{7}{3}}$ $x_(1,2)=2+-sqrt(7/3)$

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How do you solve $3 x^{2} - 12 x + 5 = 0$ $3x^2 - 12x + 5=0$ by completing the square?

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