How do you solve $(3 x + 1) - (2 x - 1) = 1$ $(3x + 1) - (2x - 1) = 1$ ?

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Answer 1 · 2015-09-25T19:13:47

$x = - 1$ $x=-1$

$(3 x + 1) - (2 x - 1) = 1$ $(3x+1)-(2x-1)=1$

Remove the parentheses, being sure to distribute the $- 1$ $-1$ in the second set of parentheses.

$3 x + 1 - 2 x + 1 = 1$ $3x+1-2x+1=1$

Combine like terms.

$x + 2 = 1$ $x+2=1$

Subtract $2$ $2$ from both sides.

$x = 1 - 2$ $x=1-2$

$x = - 1$ $x=-1$

How do you solve (3x+1)−(2x−1)=1(3x + 1) - (2x - 1) = 1?