How do you solve $(3x + 1) - (2x - 1) = 1$ ?

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Answer 1 · 2015-09-25T19:13:47

$x=-1$

$(3x+1)-(2x-1)=1$

Remove the parentheses, being sure to distribute the $-1$ in the second set of parentheses.

$3x+1-2x+1=1$

Combine like terms.

$x+2=1$

Subtract $2$ from both sides.

$x=1-2$

$x=-1$

How do you solve (3x + 1) - (2x - 1) = 1(3x + 1) - (2x - 1) = 1?