How do you solve $3 = 4 (x - 2) + 3 - 2 x$ $3= 4( x - 2) + 3- 2x$ ?

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Answer 1 · 2018-04-25T18:32:13

$x = 4$ $x = 4$

Start with the right part and solve the parentheses

$4 (x - 2) = 4 x - 8$ $4(x-2) = 4x - 8$

Rewrite your equation

$3 = 4 x - 8 + 3 - 2 x$ $3 = 4x -8 + 3 -2x$

Subtract $3$ $3$ from both sides, you have

$0 = 4 x - 8 - 2 x$ $0 = 4x - 8 - 2x$

$0 = 2 x - 8$ $0 = 2x -8$

Add $8$ $8$ to both sides

$8 = 2 x$ $8 = 2x$

Divide all by $2$ $2$

$x = 4$ $x = 4$

How do you solve 3=4(x−2)+3−2x3= 4( x - 2) + 3- 2x?