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How do you solve #2x^2-x-6=0# by factoring?

1 Answer

Oct 7, 2015

#x=-3/2#
or
#x=2#

Explanation:

#2x^2-x-6#
#color(white)("XXX")=(2x+3)(x-2)#

So #2x^2-x-6=0#
#rarrcolor(white)("XXX")(2x+3)=0color(white)("XXX)#or#color(white)("XXX)(x-2)=0#

#rarrcolor(white)("XXX")x=-3/2color(white)("XXXXX)#or#color(white)("XXX)x=2#

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