How do you solve $2 x^{2} = 8 x + 12$ $2x^2=8x+12$ by completing the square?

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Answer 1 · 2016-04-23T10:30:19

$x = 4, 0$ $x=4,0$

$2 x^{2} = 8 x + 12$ $2x^2 = 8x+12$

$\Rightarrow x^{2} = 4 x + 12$ $=> x^2 = 4x +12$

$\Rightarrow x^{2} - 4 x + 4 = 16$ $=> x^2-4x+4 = 16$

$\Rightarrow {(x - 2)}^{2} = 4^{2}$ $=> (x-2)^2 = 4^2$

$\Rightarrow x - 2 = \pm 2$ $=> x-2 = +-2$

$\Rightarrow x = 2 \pm 2$ $=> x=2+-2$

How do you solve 2x^2=8x+122x2=8x+122x^2=8x+12 by completing the square?