How do you solve $2x^2 -7x+3=0$ by completing the square?

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Answer 1 · 2017-08-17T14:33:30

$x=3$ or $x=1/2$

$2x^2-7x+3=0$

$implies 2(x^2-7/2 x)+3=0$

$implies 2(x^2-2 times 7/4 x+49/16)=49/8-3 = 25/8$

$(x-7/4)^2 = 25/16 implies x-7/4 = pm 5/4$

$implies x=7/4 pm 5/4 = 3 or 1/2$

How do you solve 2x^2 -7x+3=02x^2 -7x+3=0 by completing the square?