How do you solve $2x^2 – 2x – 3 = 0$ by completing the square?

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How do you solve $2x^2 – 2x – 3 = 0$ by completing the square?

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Answer 1 · 2016-04-23T13:10:41

$x=1/2+sqrt7/2$ and
$x=1/2-sqrt7/2$

Explanation:

In $2x^2-2x-3=0$ , let us first divide this by $2$ and we get $x^2-x-3/2=0$ . As the coefficient of $x$ is $-1$ , let us add and subtract $(-1)^2/4$ or $1/4$ , which gives us

$x^2-x+1/4-3/2-1/4=0$ or

$(x-1/2)^2-7/4=0$ or

$(x-1/2)^2-(sqrt7/2)^2=0$ or

$(x-1/2-sqrt7/2)(x-1/2+sqrt7/2)=0$ or

$x=1/2+-sqrt7/2$

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How do you solve $2x^2 – 2x – 3 = 0$ by completing the square?

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