How do you solve #2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)#?

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Answer 1 · 2017-03-25T10:17:31

#2 4/13#

#2k(-3k+4)+6(k^2+10)=k(4k+8)-2k(2k+5)#

#:.cancel(-6k^2)+8kcancel(+6k^2)+60=cancel(4k^2)-8kcancel(-4k^2)-10k#

#:.8k+60=-18k#

#:.8k+18k=-60#

#:.26k=-60#

#:.k=cancel60^color(red)30/cancel26^color(red)13#

#:.k=30/13#

#:.k=2 4/13#