How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

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How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

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Answer 1 · 2017-10-07T23:32:45

#n=-3#

Explanation:

#-26=-4(5-5n)-6(n-6)#
#-26=-20+20n-6n+36# (Removing brackets)
Bringing x terms to LHS & constant terms to RHS,
#-20n+6n=-20+36+26#
#-14n=42#
#n=-(42/14)=-3#

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How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

1 Answer

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