How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

Question

How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

1 Answer

Impact of this question

1376 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-10-07T23:32:45

#n=-3#

Explanation:

#-26=-4(5-5n)-6(n-6)#
#-26=-20+20n-6n+36# (Removing brackets)
Bringing x terms to LHS & constant terms to RHS,
#-20n+6n=-20+36+26#
#-14n=42#
#n=-(42/14)=-3#

Science

Math

Humanities

... and beyond

How do you solve #-26=-4(5-5n)-6(n-6)# using the distributive property?

1 Answer

Explanation:

Related questions

Impact of this question