How do you solve #2(2x+3)-2=5#?

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Answer 1 · 2018-06-23T00:30:47

#x = 1/4#

#2(2x+3) - 2 = 5#

First, add #color(blue)2# to both sides of the equation:
#2(2x+3) - 2 quadcolor(blue)(+quad2) = 5 quadcolor(blue)(+quad2)#

#2(2x+3) = 7#

Use the distributive property (shown below) to simplify #2(2x+3)#:
cdn.virtualnerd.com

Following this image, we know that:
#color(blue)(2(2x+3) = (2 * 2x) + (2 * 3) = 4x + 6)#

Put that back into the equation:
#4x + 6 = 7#

Subtract #color(blue)6# from both sides:
#4x + 6 quadcolor(blue)(-quad6) = 7 quadcolor(blue)(-quad6)#

#4x = 1#

Divide both sides by #color(blue)4#:
#(4x)/color(blue)4 = 1/color(blue)4#

Therefore,
#x = 1/4#

Hope this helps!