How do you solve $2 (2.5 b - 9) + 6 b = 7$ $2(2.5b -9) +6b =7$ ?

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Answer 1 · 2018-04-27T02:54:20

$b = \frac{25}{11}$ $b = 25/11$ or about $2.27$ $2.27$

$2 (2.5 b - 9) + 6 b = 7$ $2(2.5b-9)+6b = 7$

First, expand by distributing $2 (2.5 b - 9)$ $2(2.5b-9)$ :
$5 b - 18 + 6 b = 7$ $5b-18+6b=7$

Combine $5 b$ $5b$ and $6 b$ $6b$ :
$11 b - 18 = 7$ $11b - 18 = 7$

Add $18$ $color(red)(18)$ to both sides of the equation:
$11b - 18 quadcolor(red)(+quad18) = 7 quadcolor(red)(+quad18)$

$11b = 25$

Divide both sides by $11$ :
$(11b)/color(red)(11) = 25/color(red)(11)$

So the final answer is:
$b = 25/11$ or about $2.27$

Hope this helps!

How do you solve 2(2.5b -9) +6b =72(2.5b−9)+6b=72(2.5b -9) +6b =7?