How do you solve #2(13t-15)+3(t-19)=0#?

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Answer 1 · 2016-05-31T04:14:45

#t=3#

First distribute the 2 and 3 into their respective binomials. This yields

#(26t-30)+(3t-57)=0#

Now drop the parentheses and simplify to

#29t-87=0#

Now you can solve for t by adding 87 to both sides to get

#29t=87#

and dividing both sides by 29

#t=87/29=3#

You can check this answer by plugging it back into the original equation:

#2(13(3)-15)+3(3-19)=2(24)+3(-16)=48-48=0#