How do you solve $12 x^{2} = 5 x + 2$ $12x^2 = 5x + 2$ ?

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Answer 1 · 2016-06-24T18:26:51

$x = \frac{2}{3}, X = - \frac{1}{4} .$ $x=2/3, X=-1/4.$

$12 x^{2} = 5 x + 2 . \Rightarrow 12 x^{2} - 5 x - 2 = 0 .$ $12x^2=5x+2. rArr 12x^2-5x-2=0.$

Observe that, $8 \times 3 = 24, 8 - 3 = 5 .$ $8xx3=24, 8-3=5.$

Spliting $5 x$ $5x$ as $8 x - 3 x, 12 x^{2} - 8 x + 3 x - 2 = 0 .$ $8x-3x, 12x^2-8x+3x-2=0.$
$:. 4x(3x-2)+1(3x-2)=0,$ or, $(3x-2)(4x+1)=0.$

$:. 3x-2=0, or, 4x+1=0,$ giving, $x=2/3, X=-1/4.$

How do you solve 12x^2 = 5x + 212x2=5x+212x^2 = 5x + 2?