# How do you solve 10 < –3x + 1?

##### 1 Answer
May 10, 2015

$10 < - 3 x + 1$

Add $3 x$ to both sides
$3 x + 10 < 1$
Subtract $10$ from both sides
$3 x < - 9$
Divide both sides by $3$
$x < - 3$

Remember that you can perform the following operations on both sides of an inequality without changing the orientation of the inequality:
1. Add or Subtract any value
2. Multiply or Divide by any value $> 0$