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How do you solve #1/4(4)^(2x)+1=5#?

1 Answer

Sep 5, 2016

#x=1#

Explanation:

Isolate the the term with the variable:
#1/4(4)^(2x) = 4#

Get rid of the denominator:
#(4)^(2x) = 4xx4 #

Make the bases the same:
#(4)^(2x) = 4^2#

Equate the indices and solve for x:
#2x = 2#

#x = 1#

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