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How do you solve #0.25^x-0.5=2#?

1 Answer

Jul 15, 2016

#x = -0.661 #

Explanation:

#0.25^x = 2+0.5 = 2.5#

#xlog 0.25 = log2.5" take log of both sides"#

#x = (log2.5)/(log0.25)#

#x = -0.661 " 3 dp"#

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