How do you sketch one cycle of $y = - sin 2 x$ $y=-sin2x$ ?

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How do you sketch one cycle of $y = - sin 2 x$ $y=-sin2x$ ?

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Answer 1 · 2017-10-08T19:24:59

$y = sin (2 x)$ $y=sin(2x)$
graph{sin(2x) [-10, 10, -5, 5]}

Explanation:

$y = - sin (2 x)$ $y=-sin(2x)$
$x = 0, y = 0$ $x=0,y=0$
$x = \frac{π}{4}, y = - 1$ $x=pi/4,y=-1$
$x = \frac{π}{2}, y = 0$ $x=pi/2,y=0$
$x = (- \frac{π}{4}), y = 1$ $x=(-pi/4),y=1$
With these values, we can plot the graph.

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How do you sketch one cycle of $y = - sin 2 x$ $y=-sin2x$ ?

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Explanation:

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How do you sketch one cycle of $y = - sin 2 x$ $y=-sin2x$ ?