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How do you sketch one cycle of #y=-sin2x#?

1 Answer

sankarankalyanam

Oct 8, 2017

#y=sin(2x)#
graph{sin(2x) [-10, 10, -5, 5]}

Explanation:

#y=-sin(2x)#
#x=0,y=0#
#x=pi/4,y=-1#
#x=pi/2,y=0#
#x=(-pi/4),y=1#
With these values, we can plot the graph.

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