How do you simplify $(x-2)(3x-4)$ ?

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Answer 1 · 2018-03-19T22:01:52

Multiply across the parenthesis and combine like terms

$( x -2)xx (3x -4) = x xx( 3x-4) -2 ( 3x-4)$

$x xx( 3x-4) - 2(3x-4) = 3x^2 -4x - 6x + 8$

$3x^2 -4x -6x +8 = 3x^2 -10x +8$

Answer 2 · 2018-03-19T22:03:04

See a solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

$(color(red)(x) - color(red)(2))(color(blue)(3x) - color(blue)(4))$ becomes:

$(color(red)(x) xx color(blue)(3x)) - (color(red)(x) xx color(blue)(4)) - (color(red)(2) xx color(blue)(3x)) + (color(red)(2) xx color(blue)(4))$

$3x^2 - 4x - 6x + 8$

We can now combine like terms:

$3x^2 + (-4 - 6)x + 8$

$3x^2 + (-10)x + 8$

$3x^2 - 10x + 8$

Answer 3 · 2018-03-19T22:07:06

$3x^2- 10x+8$

$x ( 3x - 4) -2( 3x - 4)$

$3x^2- 4x - 6x+8$

$3x^2- 10x+8$

How do you simplify (x-2)(3x-4) (x-2)(3x-4) ?