How do you simplify #(sin^2x-1)/(1+sin^2x)#?
1 Answer
Mar 31, 2016
Explanation:
Use the Pythagorean trigonometric identity,
#(sin^2x-1)/(1+sin^2x)#
#=((1-cos^2x)-1)/(1+sin^2x)#
#=color(green)(|bar(ul(color(white)(a/a)(-cos^2x)/(1+sin^2x)color(white)(a/a)|)))#
