How do you simplify $(sin^2x-1)/(1+sin^2x)$ ?

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Answer 1 · 2016-03-31T10:49:26

$(-cos^2x)/(1+sin^2x)$

Use the Pythagorean trigonometric identity, $color(blue)(sin^2x+cos^2x=1)$ , to simplify " $sin^2x$ " in the numerator.

$(sin^2x-1)/(1+sin^2x)$

$=((1-cos^2x)-1)/(1+sin^2x)$

$=color(green)(|bar(ul(color(white)(a/a)(-cos^2x)/(1+sin^2x)color(white)(a/a)|)))$

How do you simplify (sin^2x-1)/(1+sin^2x)(sin^2x-1)/(1+sin^2x)?