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How do you simplify #Ln e^(2y)#?

1 Answer

Sep 20, 2016

#ln e^(2y)=color(green)(2y)#

Explanation:

#ln# is equivalent to #log_e#

#log_b a =c hArr b^c=a#

Therefore if #ln e^(2y) = x#
then
#color(white)("XXX")log_e e^(2y)=x#
and
#color(white)("XXX")e^x = e^(2y)#

#rarr x=2y#

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