How do you simplify #(a^2+3a)/(a^2-3a-18)# and what are the ecluded values fot he variables? Algebra Rational Equations and Functions Division of Rational Expressions 1 Answer NJ Mar 28, 2018 #=>a/(a-6)#, #a ne 6# Explanation: #=>{a^2+3a}/{a^2-3a-18}# #=>{acancel{(a+3)}}/{(a-6)cancel{(a+3)}}# #=>a/(a-6)# From this, we know: #=>a-6 ne 0# #=> a ne 6# Answer link Related questions What is Division of Rational Expressions? How does the division of rational expressions differ from the multiplication of rational expressions? How do you divide 3 rational expressions? How do you divide rational expressions? How do you divide and simplify #\frac{9x^2-4}{2x-2} -: \frac{21x^2-2x-8}{1} #? How do you divide and reduce the expression to the lowest terms #2xy \-: \frac{2x^2}{y}#? How do you divide #\frac{x^2-25}{x+3} \-: (x-5)#? How do you divide #\frac{a^2+2ab+b^2}{ab^2-a^2b} \-: (a+b)#? How do you simplify #(w^2+6w+5)/(w+5)#? How do you simplify #(x^4-256)/(x-4)#? See all questions in Division of Rational Expressions Impact of this question 1352 views around the world You can reuse this answer Creative Commons License