How do you simplify $\frac{2 x^{2} + 6 x - 8}{2}$ $( 2x^2 + 6x - 8)/(2)$ ?

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Answer 1 · 2015-07-06T10:40:35

You divide everything above and below the division bar by $2$ $2$

$= \frac{x^{2} + 3 x - 4}{1} = x^{2} + 3 x - 4$ $=(x^2+3x-4)/1=x^2+3x-4$

You may even want to factorise:

$= (x - 1) (x + 4)$ $=(x-1)(x+4)$

How do you simplify 2x2+6x−82( 2x^2 + 6x - 8)/(2)?