How do you simplify $( 2x^2 + 6x - 8)/(2)$ ?

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Answer 1 · 2015-07-06T10:40:35

You divide everything above and below the division bar by $2$

$=(x^2+3x-4)/1=x^2+3x-4$

You may even want to factorise:

$=(x-1)(x+4)$

How do you simplify ( 2x^2 + 6x - 8)/(2)( 2x^2 + 6x - 8)/(2)?