How do you simplify $- 2 c d^{2} (3 c^{2} d - 2 c d^{2} + c d^{2}$ $-2cd^2(3c^2d-2cd^2+cd^2$ ?

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Answer 1 · 2018-06-26T09:49:55

$\Rightarrow 2 c^{2} d^{3} (3 c - 2 d) = 6 c^{3} d^{3} - 4 c^{2} d^{4}$ $color(maroon)(=> 2c^2 d^3 (3c - 2d) = 6c^3d^3 - 4c^2d^4$

$- 2 c d^{2} (3 c^{2} d - 2 c d^{2} + c d^{2})$ $-2 cd^2 (3 c^2d - 2cd^2 + cd^2)$

$\Rightarrow - 2 c d^{2} (3 c^{2} d - c d^{2})$ $=>-2cd^2 (3 c^2d - cd^2)$

$\Rightarrow (2 c d^{2} \cdot c d) (3 c - 2 d)$ $=> (2cd^2 * cd ) (3c - 2d)$

$\Rightarrow 2 c^{2} d^{3} (3 c - 2 d) = 6 c^{3} d^{3} - 4 c^{2} d^{4}$ $color(maroon)(=> 2c^2 d^3 (3c - 2d) = 6c^3d^3 - 4c^2d^4$

How do you simplify −2cd2(3c2d−2cd2+cd2-2cd^2(3c^2d-2cd^2+cd^2?