How do you simplify $1 - 125tan^3s$ ?

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Answer 1 · 2018-03-16T11:45:15

$(1 - 125tan^3 s) = (1 - 5tan s) ( 1 + 5tan s + 25tan^2s)$

To simplify $1 - 125 tan^3 s$

It is in the form $a^3 - b^3$

We know $a^3 - b^3 = (a-b) * (a^2 + ab + b^2)$

Hence $(1 - 125tan^3 s) = (1 - 5tan s) ( 1 + 5tan s + 25tan^2s)$

How do you simplify 1 - 125tan^3s1 - 125tan^3s?