How do you rewrite with fractional exponents for #(root(3)(2))(root(3)(ab))#?

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1 Answer
Alan P.
Jun 10, 2015

#(root(3)(2))(root(3)(ab)) = (2^(1/3))((ab)^(1/3))" or " (2ab)^(1/3)#

Explanation:

SInce #b^m*b*n*b*p = b^(m+n+p)#
then #b^(1/3) * b^(1/3) * b^(1/3) = b^1#

also #root(3)(b) * root(3)(b) * root(3)(b) = b^1#

So #root(3)(b)# is the same as #b^(1/3)#

Replacing #b# with #2# and then with #ab# lets us derive the given solution.

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