How do you prove the identity $(tanx)/(cscx + cotx) = secx - 1$ ?

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Answer 1 · 2015-02-09T16:56:48

You can use the following points:
$tan(x)=sin(x)/c0s(x)$
$csc(x)=1/sin(x)$
$cot(x)=cos(x)/sin(x)$
$sec(x)=1/cos(x)$
and:
$sin^2(x)+cos^2(x)=1$

substituting you get:
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How do you prove the identity (tanx)/(cscx + cotx) = secx - 1(tanx)/(cscx + cotx) = secx - 1?