How do you prove that $sec^2x+csc^2x=1$ is not an identity?

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Answer 1 · 2016-11-12T12:52:44

$sec^2x+csc^2x=1/(sin^2xcos^2x)$

Since $secx=1/cosx$ and $cscx=1/sinx$ , you will get:

$sec^2x+csc^2x=1/cos^2x+1/sin^2x$

$=(sin^2x+cos^2x)/(sin^2xcos^2x)$

$=1/(sin^2xcos^2x)$

How do you prove that sec^2x+csc^2x=1sec^2x+csc^2x=1 is not an identity?