How do you prove $tan^2xsin^2x=tan^2x + cos^2x-1$ ?

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Answer 1 · 2015-05-21T15:56:51

$tan^2 x .sin^2 x = tan^2 x(1 - cos^2 x) = tan^2 x - tan^2 x(cos^2 x)$

$= tan^2 x - (sin^2 x.cos^2 x)/(cos^2 x) = tan^2 x - sin^2 x =$

$= tan^2x - 1 + cos^2 x$

How do you prove tan^2xsin^2x=tan^2x + cos^2x-1tan^2xsin^2x=tan^2x + cos^2x-1?