How do you prove $sec x csc x = sin x + cos x cot x$ $secxcscx = sinx + cosxcotx$ ?

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How do you prove $sec x csc x = sin x + cos x cot x$ $secxcscx = sinx + cosxcotx$ ?

1 Answer

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Answer 1 · 2018-03-30T16:32:28

The identity is FALSE

Explanation:

We have:

$(\frac{1}{cos x}) (\frac{1}{sin x}) = sin x + cos x (\frac{cos x}{sin x})$ $(1/cosx)(1/sinx) = sinx + cosx(cosx/sinx)$

$\frac{1}{cos x sin x} = sin x + \frac{{cos}^{2} x}{sin x}$ $1/(cosxsinx) = sinx + cos^2x/sinx$

$\frac{1}{cos x sin x} = \frac{{sin}^{2} x + {cos}^{2} x}{sin x}$ $1/(cosxsinx) = (sin^2x + cos^2x)/sinx$

$\frac{1}{cos x sin x} = \frac{1}{sin x}$ $1/(cosxsinx) = 1/sinx$

This is clearly false.

Hopefully this helps!

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How do you prove $sec x csc x = sin x + cos x cot x$ $secxcscx = sinx + cosxcotx$ ?

1 Answer

Explanation:

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Humanities

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How do you prove secxcscx=sinx+cosxcotxsecxcscx = sinx + cosxcotx?

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Explanation:

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How do you prove $sec x csc x = sin x + cos x cot x$ $secxcscx = sinx + cosxcotx$ ?