How do you prove $csc^2xtan^2x-1=tan^2x$ ?

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Answer 1 · 2015-07-03T15:31:23

Prove trig identity

$(1/(sin^2 x))(sin^2 x/cos^2 x) - 1 =$

$= (sin^2 x - sin^2 x.cos^2 x)/(sin^2 x.cos^2 x)$ =

$((sin^2 x)(1 - cos^2 x))/(sin^2x.cos^2 x) =$

= $sin^2x/cos^2 x = tan^2 x$

How do you prove csc^2xtan^2x-1=tan^2xcsc^2xtan^2x-1=tan^2x?