How do you prove #cot^-1x=tan^-1(1/x)# for x>0?

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Answer 1 · 2016-10-12T15:43:19

see below

#cot^-1x=tan^-1(1/x)#

Let #y=cot^-1x#, then by definition of inverse

#x=coty#

#x=1/tany#

#xtany=1#

#tany=1/x#

#y=tan^-1(1/x)#

#:. cot^-1x=tan^-1(1/x)#