How do you prove #cos^2theta/(1+sintheta)=1-sintheta#?

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Answer 1 · 2016-10-07T18:03:27

see below

#cos^2theta/(1+sin theta) = 1-sin theta#

Left Side : #=cos^2theta/(1+sin theta)#

#=(1-sin^2theta)/(1+sin theta)#

#=((1-sin theta)(1+sin theta))/(1+sin theta)#

#=((1-sin theta) (cancel (1+sin theta)))/(cancel(1+sin theta)#

#=1-sin theta#

#:.=# Right Side