How do you multiply (m+3)/(4m) div (m^2-9)/(32m^2(m-3))?

1 Answer
May 8, 2015

we are given :
(m+3)/(4m) / (m^2-9)/(32m^2(m-3)

for multiplying we take the reciprocal of the second term:

= (m+3)/(4m) xx 32m^2xx(m-3)/(m^2-9)

we can write
m^2-9 as (m+3)(m-3)

= (m+3)/(4m) xx 32m^2xx(m-3)/((m+3)(m-3)

= cancel(m+3)/(4m) xx 32m^2xxcancel(m-3)/(cancel(m+3)cancel(m-3)

= (32m^2) / (4m)

= 8m