How do you multiply #(k-7)^2#? Algebra Polynomials and Factoring Multiplication of Monomials by Polynomials 1 Answer Kevin G. Dec 15, 2015 #k^2 - 14k + 49# Explanation: To square a binomial, use this formula: #(a+b)^2 = a^2 + 2ab + b^2# In this case: #(k-7)^2 = (k)^2 + 2(k)(-7) + (-7)^2 = k^2 - 14k + 49# Answer link Related questions What is Multiplication of Monomials by Polynomials? How do you multiply monomials by polynomials? How do you multiply monomials by monomials? How do you multiply #(3xy^5)(-6x^4y^2)#? How do you multiply and simplify #6ab(-10a^2 b^3+c^5)#? How do you simplify #-3a^2b(9a^2-4b^2)#? How do you multiply #y(xy^4)#? How do you multiply #(2x-1)(x^3-2x^2+3x-4)#? How do you multiply #(5n^2)(2n^5 - 2n^3 3n^7)#? How do you simplify #2t^2+(3+5)(4t)#? See all questions in Multiplication of Monomials by Polynomials Impact of this question 2125 views around the world You can reuse this answer Creative Commons License