How do you multiply $- 5 c (4 c^{2} - 2 c)$ $-5c(4c^2-2c)$ ?

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Answer 1 · 2015-04-13T18:20:31

-20 $c^{3}$ $c^3$ +10 $c^{2}$ $c^2$ .

Multiply -5c with both the terms inside the parentheses
-5c(4 $c^{2}$ $c^2$ ) -5c(-2c)

= -20 $c^{3}$ $c^3$ +10 $c^{2}$ $c^2$

How do you multiply -5c(4c^2-2c)−5c(4c2−2c)-5c(4c^2-2c)?