How do you multiply $4 x y^{2} (3 x^{2} - 5 x y + 6 y^{2})$ $4xy^2(3x^2-5xy+6y^2)$ ?

Question

How do you multiply $4 x y^{2} (3 x^{2} - 5 x y + 6 y^{2})$ $4xy^2(3x^2-5xy+6y^2)$ ?

1 Answer

Impact of this question

2349 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-13T07:18:47

$12 x^{3} y^{2} - 20 x^{2} y^{3} + 24 x^{2} y^{4}$ $12x^3y^2-20x^2y^3+24x^2y^4$

Explanation:

First, we need to know that
$a^{n} \cdot a^{m} = a^{n + m}$ $a^n*a^m=a^(n+m)$

For this question, we can simply expand the bracket.
$4 x y^{2} (3 x^{2} - 5 x y + 6 y^{2})$ $4xy^2(3x^2-5xy+6y^2)$

$= 3 x^{2} \cdot 4 x y^{2} - 5 x y \cdot 4 x y^{2} + 6 y^{2} \cdot 4 x y^{2}$ $=3x^2*4xy^2-5xy*4xy^2+6y^2*4xy^2$

$= 3 \cdot 4 \cdot x^{2} \cdot x \cdot y^{2} - 5 \cdot 4 \cdot x \cdot x \cdot y \cdot y^{2} + 6 \cdot 4 \cdot x^{2} \cdot y^{2} \cdot y^{2}$ $=3*4*x^2*x*y^2-5*4*x*x*y*y^2+6*4*x^2*y^2*y^2$

$= 12 x^{2 + 1} y^{2} - 20 x^{1 + 1} y^{1 + 2} + 24 x^{2} y^{2 + 2}$ $=12x^(2+1)y^2-20x^(1+1)y^(1+2)+24x^2y^(2+2)$

$= 12 x^{3} y^{2} - 20 x^{2} y^{3} + 24 x^{2} y^{4}$ $=12x^3y^2-20x^2y^3+24x^2y^4$

Here is the answer :)

Science

Math

Humanities

... and beyond

How do you multiply $4 x y^{2} (3 x^{2} - 5 x y + 6 y^{2})$ $4xy^2(3x^2-5xy+6y^2)$ ?

1 Answer

Explanation:

Related questions

Impact of this question

Science

Math

Humanities

... and beyond

How do you multiply 4xy2(3x2−5xy+6y2)4xy^2(3x^2-5xy+6y^2)?

1 Answer

Explanation:

Related questions

Impact of this question

How do you multiply $4 x y^{2} (3 x^{2} - 5 x y + 6 y^{2})$ $4xy^2(3x^2-5xy+6y^2)$ ?