How do you multiply $4xy^2(3x^2-5xy+6y^2)$ ?

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Answer 1 · 2017-11-13T07:18:47

$12x^3y^2-20x^2y^3+24x^2y^4$

First, we need to know that
$a^n*a^m=a^(n+m)$

For this question, we can simply expand the bracket.
$4xy^2(3x^2-5xy+6y^2)$

$=3x^2*4xy^2-5xy*4xy^2+6y^2*4xy^2$

$=3*4*x^2*x*y^2-5*4*x*x*y*y^2+6*4*x^2*y^2*y^2$

$=12x^(2+1)y^2-20x^(1+1)y^(1+2)+24x^2y^(2+2)$

$=12x^3y^2-20x^2y^3+24x^2y^4$

Here is the answer :)

How do you multiply 4xy^2(3x^2-5xy+6y^2)4xy^2(3x^2-5xy+6y^2)?