How do you multiply -3y^2-4y+6+2(y^2+7y-1)?

1 Answer
Jul 28, 2015

You expand the paranthesis and add or subtract like terms.

Explanation:

Your starting expression is

-3y^2 - 4y + 6 + 2(y^2 + 7y - 1)

Notice that your expression contains the product between 2 and a paranthesis that features three terms, y^2, 7y, and -1.

To expand this paranthesis, multiply each of these terms by 2 to get

2(y^2 + 7y - 1) = 2* y^2 + 2 * 7y + 2 * (-1)=2y^2 + 14y - 2

Your expression becomes

-3y^2 - 4y + 6 + 2y^2 + 14y - 2

You can simplify this further by grouping like terms together to get

(-3y^2 + 2y^2) +(14y - 4y) + (6-2)

color(green)(-y^2 + 10y + 4)