How do you multiply $2y(y-4)$ ?

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Answer 1 · 2017-04-28T05:26:37

$2y^2 - 8y$

Use distribution $a(b + c) = ab + ac$ and the exponent rules $x = x^1 " and " x^m * x^n = x^(m + n)$ :

Given: $2y (y - 4)$

Distribute: $2y (y - 4) = 2y y + 2y(-4)$

Simplify using multiplication and the exponent rules:

$= 2y^2 -8y$

How do you multiply 2y(y-4)2y(y-4)?