How do you multiply $- 2 x (x^{2} - 3)$ $-2x(x^2 - 3)$ ?

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Answer 1 · 2016-02-12T17:03:28

$= - 2 x^{3} + 6 x$ $= color(blue)( -2x^3 +6x$

$- 2 x (x^{2} - 3)$ $color(green)(-2x) (x^2-3)$

$- 2 x$ $color(green)(-2x)$ is multiplied with both terms within the bracket.

$= (- 2 x) \times (x^{2}) + (- 2 x) \times (- 3)$ $= color(green)((-2x)) xx (x^2) + color(green)( (-2x)) xx (-3)$

$= - 2 x^{3} + 6 x$ $= -2x^3 +6x$

How do you multiply -2x(x^2 - 3)−2x(x2−3)-2x(x^2 - 3)?